4x-8x^2=x2

Solution for 4x-8x^2=x2 equation:

4x-8x^2=x2

We move all terms to the left:

4x-8x^2-(x2)=0

We add all the numbers together, and all the variables

-9x^2+4x=0

a = -9; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-9)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-9}=\frac{-8}{-18}
=4/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-9}=\frac{0}{-18}
=0
$